Have you ever wondered how a massive steel ship floats on water while a small nail sinks? Or how a submarine can dive deep and then rise back to the surface? Or why a hot air balloon floats into the sky? These are some of the most fascinating questions in physics, and they all come down to one beautiful principle: Archimedes' principle.
Floating and sinking are not just about weight. They are about density, upthrust, and the delicate balance between the weight of an object and the weight of the fluid it displaces. Understanding these ideas explains why we can build ships that carry thousands of tonnes, why life jackets save lives, and why the human body can float in the Dead Sea but not in a swimming pool. Let us dive into this fascinating topic together.
I once asked a class, "Why does a ship float?" A student said, "Because it is light." I said, "A ship can weigh more than a thousand elephants. Is that light?" The class fell silent. Then I explained: a ship floats not because it is light, but because it is shaped in a way that displaces a lot of water. The weight of the water displaced equals the weight of the ship. That is Archimedes' principle. Once they understood this, their view of the world changed.By the end of this chapter, you should be able to:
Before we can understand floating and sinking, we must understand density. Density is how much mass is packed into a given volume.
Density: ρ = m / V
ρ = density (kg/m³), m = mass (kg), V = volume (m³)
Key idea: Whether an object floats or sinks depends on its density compared to the density of the fluid it is placed in.
| Comparison | Result | Example |
|---|---|---|
| Object density < fluid density | Floats | Wood (600 kg/m³) in water (1 000 kg/m³) |
| Object density = fluid density | Neutral (stays at any depth) | A submarine at neutral buoyancy |
| Object density > fluid density | Sinks | Iron (7 800 kg/m³) in water (1 000 kg/m³) |
Think of a crowded room. If you are denser than the crowd, you sink to the bottom. If you are less dense, you rise to the top. The same idea applies to objects in fluids.
Density is the secret behind floating and sinking. A solid steel block sinks because steel is denser than water. But a steel ship floats because it is hollow — its average density (including the air inside) is less than the density of water. Same material, different shape, different result. Physics is wonderful.When an object is placed in a fluid, the fluid exerts an upward force on it. This force is called upthrust or buoyant force.
Why does upthrust exist? Because fluid pressure increases with depth. The pressure on the bottom of the object is greater than the pressure on the top. This difference in pressure creates a net upward force.
Think of a balloon underwater. The water pushes up on the bottom of the balloon more than it pushes down on the top. The result is an upward force — upthrust.
| Depth | Pressure | Effect |
|---|---|---|
| Shallow (top of object) | Lower | Less force pushing down |
| Deep (bottom of object) | Higher | More force pushing up |
| Difference | — | Net upward force (upthrust) |
Factors affecting upthrust:
Upthrust does not depend on:
Archimedes' principle states: When an object is wholly or partially immersed in a fluid, the upthrust on the object is equal to the weight of the fluid displaced.
Archimedes' principle: Upthrust = Weight of fluid displaced
Upthrust = ρ_fluid × V_displaced × g
ρ_fluid = density of fluid (kg/m³), V_displaced = volume of fluid displaced (m³), g = gravitational field strength (N/kg)
Think of getting into a full bathtub. Water spills over the edge. The amount of water that spills out is the volume of your body that is submerged. According to Archimedes, the upthrust you feel is equal to the weight of that spilled water.
Apparent weight: The weight of an object when submerged in a fluid is less than its weight in air. This is because upthrust acts upward, opposing gravity.
Apparent weight: W_apparent = W_actual − Upthrust
W_apparent = weight in fluid (N), W_actual = weight in air (N), Upthrust = buoyant force (N)
This is why objects feel lighter in water. A heavy stone that is difficult to lift on land becomes easier to lift when it is submerged.
| Situation | Weight in Air | Upthrust | Apparent Weight |
|---|---|---|---|
| Stone in air | 50 N | 0 N | 50 N |
| Stone in water | 50 N | 20 N | 30 N |
| Stone in mercury | 50 N | 40 N | 10 N |
The law of flotation states: A floating object displaces its own weight of the fluid in which it floats.
Law of flotation: Weight of floating object = Weight of fluid displaced
For a floating object: Upthrust = Weight of object
Why is this true? Because a floating object is in equilibrium — it is not accelerating up or down. The upward force (upthrust) must equal the downward force (weight).
Think of a boat floating on water. The boat is not sinking or rising, so the forces on it must be balanced. The upthrust from the water equals the weight of the boat. According to Archimedes, the upthrust equals the weight of the water displaced. So the boat displaces its own weight of water.
| Object | Weight | Weight of Water Displaced | Fraction Submerged |
|---|---|---|---|
| Wooden block | 6 N | 6 N | Partially submerged |
| Ship | 1 000 000 N | 1 000 000 N | Partially submerged |
| Iceberg | — | Equal to weight of iceberg | About 90% submerged |
Relative density (also called specific gravity) is the ratio of the density of a substance to the density of water.
Relative density: RD = density of substance / density of water
RD = (mass of substance) / (mass of equal volume of water)
Relative density has no units because it is a ratio.
Interpretation:
| Substance | Density (kg/m³) | Relative Density | Floats or Sinks? |
|---|---|---|---|
| Wood (oak) | 600 | 0.6 | Floats |
| Ice | 920 | 0.92 | Floats |
| Water | 1 000 | 1.0 | — |
| Aluminium | 2 700 | 2.7 | Sinks |
| Iron | 7 800 | 7.8 | Sinks |
| Mercury | 13 600 | 13.6 | Sinks (in water) |
Using relative density to find density:
Density of substance = RD × density of water
Density of water = 1 000 kg/m³ (or 1 g/cm³)
A hydrometer is an instrument used to measure the relative density of liquids. It works on the principle of flotation.
Construction:
How it works:
| Liquid | Density (kg/m³) | Hydrometer Reading |
|---|---|---|
| Petrol | 700 | 0.7 |
| Water | 1 000 | 1.0 |
| Sea water | 1 025 | 1.025 |
| Glycerine | 1 260 | 1.26 |
Uses of hydrometers:
How does a huge steel ship float? After all, steel is much denser than water.
The secret is shape. A ship is hollow and shaped like a bowl. This means it has a large volume, so it displaces a large volume of water. Even though the steel is dense, the average density of the ship (including the air inside) is less than the density of water.
Key points:
| Condition | Ship's Position | Upthrust vs Weight |
|---|---|---|
| Empty | Sits high in water | Upthrust = Weight |
| Partially loaded | Sits lower | Upthrust = Weight |
| Fully loaded | At Plimsoll line | Upthrust = Weight |
| Overloaded | Below Plimsoll line | Upthrust < Weight (danger) |
A submarine can float on the surface, dive to any depth, and return to the surface. How does it do this?
The secret is ballast tanks. A submarine has large tanks that can be filled with water or air.
How it works:
| Action | Ballast Tanks | Average Density | Result |
|---|---|---|---|
| Dive | Filled with water | Greater than water | Sinks |
| Rise | Filled with air | Less than water | Floats up |
| Neutral | Partially filled | Equal to water | Stays at depth |
A hot air balloon rises because the air inside the balloon is less dense than the air outside.
How it works:
Think of a hot air balloon as a bubble of warm, light air in a sea of cooler, denser air. The warm air rises because it is less dense, just as a bubble of air rises in water.
| Action | Air Inside Balloon | Density | Result |
|---|---|---|---|
| Heat air | Expands | Less than outside air | Rises |
| Cool air | Contracts | More than outside air | Descends |
| Neutral | Same temperature | Equal to outside air | Stays at altitude |
Floating and sinking are not just human concerns — they are vital to life on Earth.
| Natural Phenomenon | How It Works |
|---|---|
| Ice floats on water | Ice is less dense than water (0.92 g/cm³ vs 1.0 g/cm³) |
| Fish control depth | Swim bladder adjusts gas content to change density |
| Plankton floats | Lipids and gas bubbles reduce density |
| Birds float on water | Feathers trap air, reducing average density |
| Dead Sea floating | High salt content increases water density |
| Continents float on mantle | Less dense continental crust floats on denser mantle |
Why ice floats: Water is unusual — it expands when it freezes. This makes ice less dense than liquid water. If ice sank, lakes and oceans would freeze from the bottom up, killing aquatic life. Because ice floats, it forms an insulating layer on top, allowing life to survive beneath.
The fact that ice floats is one of the reasons life exists on Earth. If ice sank, the oceans would freeze solid, and life as we know it would be impossible. This is a beautiful example of how a simple physical property — the density of ice — has profound consequences for the entire planet.| Application | How It Works |
|---|---|
| Ships | Hollow shape displaces large volume of water |
| Submarines | Ballast tanks control average density |
| Hot air balloons | Heated air is less dense than surrounding air |
| Hydrometers | Float at different depths depending on liquid density |
| Life jackets | Increase volume, reducing average density |
| Swim bladders in fish | Adjust gas content to control depth |
| Plimsoll line | Marks maximum safe loading depth for ships |
| Car battery testing | Hydrometer measures acid density |
Density: ρ = m / V
Archimedes' principle: Upthrust = Weight of fluid displaced = ρ_fluid × V_displaced × g
Apparent weight: W_apparent = W_actual − Upthrust
Law of flotation: Weight of floating object = Weight of fluid displaced
Relative density: RD = density of substance / density of water
Density of substance: ρ = RD × 1 000 kg/m³
Density of water: 1 000 kg/m³ = 1 g/cm³
Gravitational field strength: g = 10 N/kg
Question: A stone of volume 0.002 m³ is fully submerged in water. Calculate the upthrust on the stone. Density of water = 1 000 kg/m³, g = 10 N/kg.
Answer:
Formula: Upthrust = ρ_fluid × V_displaced × g
Substitution: Upthrust = 1 000 × 0.002 × 10
Answer: Upthrust = 20 N
Units check: kg/m³ × m³ × N/kg = N. The answer is in newtons, correct for force. Notice that the upthrust depends only on the volume of water displaced and the density of water, not on the mass of the stone.Question: A stone weighs 50 N in air. When fully submerged in water, it weighs 30 N. Calculate the upthrust and the volume of the stone. Density of water = 1 000 kg/m³, g = 10 N/kg.
Answer:
Upthrust = W_actual − W_apparent = 50 − 30 = 20 N
Volume: Upthrust = ρ × V × g → 20 = 1 000 × V × 10 → V = 20 / 10 000 = 0.002 m³
Answer: Upthrust = 20 N, Volume = 0.002 m³
Units check: the answer is in N and m³. Notice that we used the apparent weight to find the upthrust. This is a common experimental method for finding the volume of an irregular object.Question: A metal block has a mass of 540 g and a volume of 200 cm³. Calculate its density and relative density. Will it float or sink in water?
Answer:
Density = m / V = 540 g / 200 cm³ = 2.7 g/cm³ = 2 700 kg/m³
Relative density = density of substance / density of water = 2.7 / 1 = 2.7
Since RD > 1, the metal will sink in water.
Units check: the answer is in g/cm³ and kg/m³. Notice that the relative density has no units. Does 2.7 make sense? Yes, this is the relative density of aluminium.Question: A wooden block floats in water with 60% of its volume submerged. The density of water is 1 000 kg/m³. Calculate the density of the wood.
Answer:
Let V be the total volume of the wood. Volume submerged = 0.6V.
By the law of flotation: Weight of wood = Weight of water displaced
ρ_wood × V × g = ρ_water × 0.6V × g
ρ_wood = 0.6 × ρ_water = 0.6 × 1 000 = 600 kg/m³
Answer: The density of the wood is 600 kg/m³.
Units check: the answer is in kg/m³. Notice that the fraction submerged equals the relative density of the wood. This is a useful shortcut: for a floating object, the fraction submerged = RD of the object.Question: A hydrometer floats in water with 8 cm of its stem above the surface. When placed in another liquid, 6 cm of its stem is above the surface. Calculate the relative density of the liquid.
Answer:
Let the total length of the stem be L and the volume of the hydrometer be V.
In water: Volume submerged = V − A × 0.08 (where A is the cross-sectional area of the stem)
In liquid: Volume submerged = V − A × 0.06
By the law of flotation: Weight of hydrometer = Weight of fluid displaced
In water: W = ρ_water × (V − 0.08A) × g
In liquid: W = ρ_liquid × (V − 0.06A) × g
Equating: ρ_water × (V − 0.08A) = ρ_liquid × (V − 0.06A)
This is complex without knowing V and A. However, in a typical problem, the hydrometer is designed so that the stem is uniform and the volume submerged is approximately equal to the total volume minus the exposed stem. A simpler approach: the relative density is the ratio of the submerged lengths (if the stem is uniform). RD = (L − 0.06) / (L − 0.08). Without L, we cannot solve numerically. Let us assume the hydrometer has a total length of 0.2 m. Then RD = (0.2 − 0.06) / (0.2 − 0.08) = 0.14 / 0.12 = 1.17.
Answer: The relative density of the liquid is approximately 1.17.
Units check: relative density has no units. This problem shows how a hydrometer works — the depth to which it sinks depends on the density of the liquid. In a denser liquid, it sinks less. In a less dense liquid, it sinks more.Graphs help us understand the relationships in floating and sinking.
Upthrust vs depth (for a fully submerged object): If you plot upthrust on the vertical axis and depth on the horizontal axis, you get a horizontal line. Once the object is fully submerged, the upthrust remains constant regardless of depth.
Upthrust vs volume submerged: If you plot upthrust on the vertical axis and volume submerged on the horizontal axis, you get a straight line through the origin. Upthrust is directly proportional to the volume of fluid displaced.
Apparent weight vs volume submerged: If you plot apparent weight on the vertical axis and volume submerged on the horizontal axis, you get a straight line with a negative gradient. The apparent weight decreases as more of the object is submerged.
These graphs help us visualise the relationships in floating and sinking. They turn equations into pictures.
Think of a graph as a map of a relationship. The shape tells you how one quantity changes with another.
Apparatus: A spring balance, a stone, a beaker, water, a measuring cylinder, and a retort stand.
Method:
Calculation: If W_air = 50 N, W_water = 30 N, V = 0.002 m³, ρ = 1 000 kg/m³, g = 10 N/kg:
Upthrust = 50 − 30 = 20 N
Weight of water displaced = 1 000 × 0.002 × 10 = 20 N
They are equal — Archimedes' principle is verified.
Precautions:
Likely source of error: Air bubbles clinging to the stone can affect the volume reading. Tap the stone gently to dislodge bubbles.
This experiment is a classic for a reason. It verifies Archimedes' principle directly and gives you a hands-on understanding of upthrust. Once you see the numbers match, the principle becomes real. It is a beautiful moment in any physics course.Upthrust is the upward force exerted by a fluid on an object placed in it.
When an object is wholly or partially immersed in a fluid, the upthrust on the object is equal to the weight of the fluid displaced.
A floating object displaces its own weight of the fluid in which it floats.
Relative density is the ratio of the density of a substance to the density of water.
Upthrust = ρ × V × g = 1 000 × 0.003 × 10 = 30 N.
A ship floats because it is hollow and displaces a large volume of water. The upthrust equals the weight of the ship, so it floats.
A submarine fills its ballast tanks with water to increase its average density and dive. It pumps air into the tanks to decrease its average density and rise.
Water expands when it freezes, so the same mass of ice occupies a larger volume than liquid water. This makes ice less dense.
(a) State Archimedes' principle. [2]
(b) A stone of volume 0.004 m³ is fully submerged in water. Calculate the upthrust on the stone. Density of water = 1 000 kg/m³, g = 10 N/kg. [3]
(c) The stone weighs 80 N in air. Calculate its apparent weight in water. [3]
(a) When an object is wholly or partially immersed in a fluid, the upthrust on the object is equal to the weight of the fluid displaced. (2 marks.)
(b) Upthrust = ρ × V × g = 1 000 × 0.004 × 10 = 40 N. (3 marks.)
(c) Apparent weight = 80 − 40 = 40 N. (3 marks.)
(a) Define relative density and state its significance. [3]
(b) A metal block has a mass of 810 g and a volume of 300 cm³. Calculate its density and relative density. Will it float or sink in water? [5]
(c) Explain why a ship made of steel floats even though steel is denser than water. [3]
(a) Relative density is the ratio of the density of a substance to the density of water. It has no units. RD < 1 means float; RD > 1 means sink. (3 marks.)
(b) Density = 810/300 = 2.7 g/cm³ = 2 700 kg/m³. RD = 2.7. Since RD > 1, it sinks. (5 marks.)
(c) A ship is hollow, so its average density (including the air inside) is less than the density of water. It displaces a large volume of water, and the upthrust equals its weight. (3 marks.)
(a) Describe how a hydrometer works. [4]
(b) A wooden block floats in water with 70% of its volume submerged. Calculate the density of the wood. Density of water = 1 000 kg/m³. [4]
(c) Explain why a hot air balloon rises when the air inside is heated. [3]
(a) A hydrometer is a sealed tube with a weighted bulb. It floats in a liquid, and the depth to which it sinks depends on the liquid's density. The relative density is read from the scale at the liquid surface. (4 marks.)
(b) Fraction submerged = RD of wood = 0.7. Density = 0.7 × 1 000 = 700 kg/m³. (4 marks.)
(c) Heating the air inside the balloon makes it expand and become less dense than the surrounding air. The upthrust is greater than the weight, so the balloon rises. (3 marks.)
Explain why a person can float more easily in the Dead Sea than in a swimming pool.
The Dead Sea has a very high salt content, making its water much denser than fresh water. A denser fluid provides more upthrust for the same volume displaced. So a person floats higher in the Dead Sea because the water displaces more weight for the same submerged volume.
A block of ice floats in water. When it melts, does the water level rise, fall, or stay the same? Explain.
The water level stays the same. The floating ice displaces its own weight of water. When it melts, it becomes water of the same weight, which occupies the same volume as the water it displaced. So the level does not change.
Explain why a ship sinks if it is overloaded, using Archimedes' principle.
A ship floats because the upthrust equals its weight. If it is overloaded, its weight increases. To balance this, it must displace more water, so it sinks deeper. If the weight becomes so great that the ship cannot displace enough water (because the deck goes below the surface), the upthrust can no longer equal the weight, and the ship sinks.
Floating and sinking are not about weight alone — they are about the delicate balance between an object's weight and the weight of the fluid it displaces. In that balance, we find ships, submarines, and the beauty of Archimedes' principle.