Chapter 3: Floating and Sinking

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Chapter 3: Floating and Sinking

1. Why This Matters

Have you ever wondered how a massive steel ship floats on water while a small nail sinks? Or how a submarine can dive deep and then rise back to the surface? Or why a hot air balloon floats into the sky? These are some of the most fascinating questions in physics, and they all come down to one beautiful principle: Archimedes' principle.

Floating and sinking are not just about weight. They are about density, upthrust, and the delicate balance between the weight of an object and the weight of the fluid it displaces. Understanding these ideas explains why we can build ships that carry thousands of tonnes, why life jackets save lives, and why the human body can float in the Dead Sea but not in a swimming pool. Let us dive into this fascinating topic together.

I once asked a class, "Why does a ship float?" A student said, "Because it is light." I said, "A ship can weigh more than a thousand elephants. Is that light?" The class fell silent. Then I explained: a ship floats not because it is light, but because it is shaped in a way that displaces a lot of water. The weight of the water displaced equals the weight of the ship. That is Archimedes' principle. Once they understood this, their view of the world changed.

2. Learning Objectives

By the end of this chapter, you should be able to:

  • Define upthrust (buoyant force) and explain its origin.
  • State Archimedes' principle and apply it to solve problems.
  • Calculate upthrust using the weight of the fluid displaced.
  • Explain the relationship between density and floating.
  • State the law of flotation.
  • Define relative density and calculate it.
  • Describe how a hydrometer works and its uses.
  • Explain how ships, submarines, and hot air balloons float and sink.
  • Appreciate the importance of floating and sinking in nature, technology, and daily life.

3. Concept Build-Up

3.1 Density — The Key to Floating and Sinking

Before we can understand floating and sinking, we must understand density. Density is how much mass is packed into a given volume.

Density: ρ = m / V

ρ = density (kg/m³), m = mass (kg), V = volume (m³)

Key idea: Whether an object floats or sinks depends on its density compared to the density of the fluid it is placed in.

ComparisonResultExample
Object density < fluid densityFloatsWood (600 kg/m³) in water (1 000 kg/m³)
Object density = fluid densityNeutral (stays at any depth)A submarine at neutral buoyancy
Object density > fluid densitySinksIron (7 800 kg/m³) in water (1 000 kg/m³)

Think of a crowded room. If you are denser than the crowd, you sink to the bottom. If you are less dense, you rise to the top. The same idea applies to objects in fluids.

Density is the secret behind floating and sinking. A solid steel block sinks because steel is denser than water. But a steel ship floats because it is hollow — its average density (including the air inside) is less than the density of water. Same material, different shape, different result. Physics is wonderful.

3.2 Upthrust (Buoyant Force)

When an object is placed in a fluid, the fluid exerts an upward force on it. This force is called upthrust or buoyant force.

Why does upthrust exist? Because fluid pressure increases with depth. The pressure on the bottom of the object is greater than the pressure on the top. This difference in pressure creates a net upward force.

Think of a balloon underwater. The water pushes up on the bottom of the balloon more than it pushes down on the top. The result is an upward force — upthrust.

DepthPressureEffect
Shallow (top of object)LowerLess force pushing down
Deep (bottom of object)HigherMore force pushing up
Difference—Net upward force (upthrust)

Factors affecting upthrust:

  • The density of the fluid (denser fluid = more upthrust).
  • The volume of the object submerged (more volume = more upthrust).
  • The gravitational field strength (g).

Upthrust does not depend on:

  • The mass of the object.
  • The shape of the object.
  • The depth of the object (as long as it is fully submerged).
Upthrust is a consequence of pressure increasing with depth. It is one of those beautiful ideas where a simple observation — pressure increases with depth — leads to a profound result: fluids push up on objects. This is why you feel lighter in water and why it is easier to lift a heavy object when it is submerged.

3.3 Archimedes' Principle

Archimedes' principle states: When an object is wholly or partially immersed in a fluid, the upthrust on the object is equal to the weight of the fluid displaced.

Archimedes' principle: Upthrust = Weight of fluid displaced

Upthrust = ρ_fluid × V_displaced × g

ρ_fluid = density of fluid (kg/m³), V_displaced = volume of fluid displaced (m³), g = gravitational field strength (N/kg)

Think of getting into a full bathtub. Water spills over the edge. The amount of water that spills out is the volume of your body that is submerged. According to Archimedes, the upthrust you feel is equal to the weight of that spilled water.

Apparent weight: The weight of an object when submerged in a fluid is less than its weight in air. This is because upthrust acts upward, opposing gravity.

Apparent weight: W_apparent = W_actual − Upthrust

W_apparent = weight in fluid (N), W_actual = weight in air (N), Upthrust = buoyant force (N)

This is why objects feel lighter in water. A heavy stone that is difficult to lift on land becomes easier to lift when it is submerged.

SituationWeight in AirUpthrustApparent Weight
Stone in air50 N0 N50 N
Stone in water50 N20 N30 N
Stone in mercury50 N40 N10 N
Archimedes' principle is one of the most elegant and useful principles in all of physics. It was discovered by Archimedes over 2 000 years ago, and it is still used today to design ships, submarines, and hot air balloons. The story goes that he was so excited by his discovery that he ran through the streets shouting "Eureka!" — "I have found it!" That is the joy of physics.

3.4 The Law of Flotation

The law of flotation states: A floating object displaces its own weight of the fluid in which it floats.

Law of flotation: Weight of floating object = Weight of fluid displaced

For a floating object: Upthrust = Weight of object

Why is this true? Because a floating object is in equilibrium — it is not accelerating up or down. The upward force (upthrust) must equal the downward force (weight).

Think of a boat floating on water. The boat is not sinking or rising, so the forces on it must be balanced. The upthrust from the water equals the weight of the boat. According to Archimedes, the upthrust equals the weight of the water displaced. So the boat displaces its own weight of water.

ObjectWeightWeight of Water DisplacedFraction Submerged
Wooden block6 N6 NPartially submerged
Ship1 000 000 N1 000 000 NPartially submerged
Iceberg—Equal to weight of icebergAbout 90% submerged
The law of flotation explains why a ship can carry a huge load. As you add cargo, the ship sinks deeper into the water, displacing more water. The upthrust increases until it equals the total weight of the ship plus cargo. This is why ships have a Plimsoll line — a mark that shows the maximum safe loading depth.

3.5 Relative Density

Relative density (also called specific gravity) is the ratio of the density of a substance to the density of water.

Relative density: RD = density of substance / density of water

RD = (mass of substance) / (mass of equal volume of water)

Relative density has no units because it is a ratio.

Interpretation:

  • RD > 1: substance is denser than water and will sink.
  • RD < 1: substance is less dense than water and will float.
  • RD = 1: substance has the same density as water.
SubstanceDensity (kg/m³)Relative DensityFloats or Sinks?
Wood (oak)6000.6Floats
Ice9200.92Floats
Water1 0001.0—
Aluminium2 7002.7Sinks
Iron7 8007.8Sinks
Mercury13 60013.6Sinks (in water)

Using relative density to find density:

Density of substance = RD × density of water

Density of water = 1 000 kg/m³ (or 1 g/cm³)

Relative density is a very useful concept because it avoids the need to remember the density of water in different units. If you know the relative density of a substance, you can immediately tell whether it will float or sink in water. RD less than 1 — it floats. RD greater than 1 — it sinks. Simple.

3.6 Hydrometers

A hydrometer is an instrument used to measure the relative density of liquids. It works on the principle of flotation.

Construction:

  • A sealed glass tube with a weighted bulb at the bottom.
  • The stem is graduated with a scale.
  • It floats upright in the liquid being tested.

How it works:

  1. The hydrometer floats in the liquid.
  2. The depth to which it sinks depends on the density of the liquid.
  3. In a denser liquid, it sinks less (floats higher).
  4. In a less dense liquid, it sinks more (floats lower).
  5. The relative density is read from the scale at the liquid surface.
LiquidDensity (kg/m³)Hydrometer Reading
Petrol7000.7
Water1 0001.0
Sea water1 0251.025
Glycerine1 2601.26

Uses of hydrometers:

  • Checking the state of charge of a car battery (by measuring the density of the acid).
  • Measuring the alcohol content of liquids.
  • Testing the purity of milk.
  • Measuring the density of urine in medical tests.
The hydrometer is a beautiful application of Archimedes' principle. It is simple, reliable, and has been used for centuries. The next time you see one, remember: it floats because of upthrust, and it measures density because of how deeply it sinks. Physics in your hand.

3.7 Ships and Boats

How does a huge steel ship float? After all, steel is much denser than water.

The secret is shape. A ship is hollow and shaped like a bowl. This means it has a large volume, so it displaces a large volume of water. Even though the steel is dense, the average density of the ship (including the air inside) is less than the density of water.

Key points:

  • A ship floats because it displaces its own weight of water.
  • As cargo is added, the ship sinks deeper, displacing more water.
  • The Plimsoll line marks the maximum safe loading depth.
  • If the ship is overloaded, it may sink below the Plimsoll line and be in danger of sinking.
ConditionShip's PositionUpthrust vs Weight
EmptySits high in waterUpthrust = Weight
Partially loadedSits lowerUpthrust = Weight
Fully loadedAt Plimsoll lineUpthrust = Weight
OverloadedBelow Plimsoll lineUpthrust < Weight (danger)
The Plimsoll line is a life-saving invention. It was introduced by Samuel Plimsoll in the 19th century to prevent ships from being overloaded and sinking. It is a simple mark on the side of a ship, but it has saved thousands of lives. Physics is not just about understanding — it is about safety.

3.8 Submarines

A submarine can float on the surface, dive to any depth, and return to the surface. How does it do this?

The secret is ballast tanks. A submarine has large tanks that can be filled with water or air.

How it works:

  • To dive: The ballast tanks are filled with water. The submarine's average density increases, so it sinks.
  • To rise: Compressed air is pumped into the ballast tanks, forcing the water out. The submarine's average density decreases, so it rises.
  • To stay at a constant depth: The ballast tanks are partially filled so that the submarine's average density equals the density of water (neutral buoyancy).
ActionBallast TanksAverage DensityResult
DiveFilled with waterGreater than waterSinks
RiseFilled with airLess than waterFloats up
NeutralPartially filledEqual to waterStays at depth
The submarine is a brilliant example of how controlling density allows an object to move up and down in a fluid. It is the same principle that allows a hot air balloon to rise and fall — by changing its average density. Physics gives us mastery over the vertical dimension.

3.9 Hot Air Balloons

A hot air balloon rises because the air inside the balloon is less dense than the air outside.

How it works:

  1. The burner heats the air inside the balloon.
  2. Hot air expands and becomes less dense.
  3. The less dense air inside the balloon creates an upthrust greater than the weight of the balloon and its payload.
  4. The balloon rises.
  5. To descend, the air inside is allowed to cool, increasing its density.

Think of a hot air balloon as a bubble of warm, light air in a sea of cooler, denser air. The warm air rises because it is less dense, just as a bubble of air rises in water.

ActionAir Inside BalloonDensityResult
Heat airExpandsLess than outside airRises
Cool airContractsMore than outside airDescends
NeutralSame temperatureEqual to outside airStays at altitude
The hot air balloon is one of the oldest and most beautiful applications of Archimedes' principle. It was invented in 1783 by the Montgolfier brothers, and it still captures our imagination today. The next time you see one, remember: it floats because of physics.

3.10 Floating and Sinking in Nature

Floating and sinking are not just human concerns — they are vital to life on Earth.

Natural PhenomenonHow It Works
Ice floats on waterIce is less dense than water (0.92 g/cm³ vs 1.0 g/cm³)
Fish control depthSwim bladder adjusts gas content to change density
Plankton floatsLipids and gas bubbles reduce density
Birds float on waterFeathers trap air, reducing average density
Dead Sea floatingHigh salt content increases water density
Continents float on mantleLess dense continental crust floats on denser mantle

Why ice floats: Water is unusual — it expands when it freezes. This makes ice less dense than liquid water. If ice sank, lakes and oceans would freeze from the bottom up, killing aquatic life. Because ice floats, it forms an insulating layer on top, allowing life to survive beneath.

The fact that ice floats is one of the reasons life exists on Earth. If ice sank, the oceans would freeze solid, and life as we know it would be impossible. This is a beautiful example of how a simple physical property — the density of ice — has profound consequences for the entire planet.

3.11 Applications of Floating and Sinking

ApplicationHow It Works
ShipsHollow shape displaces large volume of water
SubmarinesBallast tanks control average density
Hot air balloonsHeated air is less dense than surrounding air
HydrometersFloat at different depths depending on liquid density
Life jacketsIncrease volume, reducing average density
Swim bladders in fishAdjust gas content to control depth
Plimsoll lineMarks maximum safe loading depth for ships
Car battery testingHydrometer measures acid density
Floating and sinking are everywhere in technology and nature. Every time you see a ship, a submarine, or a hot air balloon, you are seeing Archimedes' principle in action. It is one of the most practical and beautiful topics in all of physics.

4. Formula Box

Density: ρ = m / V

Archimedes' principle: Upthrust = Weight of fluid displaced = ρ_fluid × V_displaced × g

Apparent weight: W_apparent = W_actual − Upthrust

Law of flotation: Weight of floating object = Weight of fluid displaced

Relative density: RD = density of substance / density of water

Density of substance: ρ = RD × 1 000 kg/m³

Density of water: 1 000 kg/m³ = 1 g/cm³

Gravitational field strength: g = 10 N/kg

5. Worked Examples

Example 1: Calculating Upthrust

Question: A stone of volume 0.002 m³ is fully submerged in water. Calculate the upthrust on the stone. Density of water = 1 000 kg/m³, g = 10 N/kg.

Answer:

Formula: Upthrust = ρ_fluid × V_displaced × g

Substitution: Upthrust = 1 000 × 0.002 × 10

Answer: Upthrust = 20 N

Units check: kg/m³ × m³ × N/kg = N. The answer is in newtons, correct for force. Notice that the upthrust depends only on the volume of water displaced and the density of water, not on the mass of the stone.

Example 2: Apparent Weight

Question: A stone weighs 50 N in air. When fully submerged in water, it weighs 30 N. Calculate the upthrust and the volume of the stone. Density of water = 1 000 kg/m³, g = 10 N/kg.

Answer:

Upthrust = W_actual − W_apparent = 50 − 30 = 20 N

Volume: Upthrust = ρ × V × g → 20 = 1 000 × V × 10 → V = 20 / 10 000 = 0.002 m³

Answer: Upthrust = 20 N, Volume = 0.002 m³

Units check: the answer is in N and m³. Notice that we used the apparent weight to find the upthrust. This is a common experimental method for finding the volume of an irregular object.

Example 3: Relative Density

Question: A metal block has a mass of 540 g and a volume of 200 cm³. Calculate its density and relative density. Will it float or sink in water?

Answer:

Density = m / V = 540 g / 200 cm³ = 2.7 g/cm³ = 2 700 kg/m³

Relative density = density of substance / density of water = 2.7 / 1 = 2.7

Since RD > 1, the metal will sink in water.

Units check: the answer is in g/cm³ and kg/m³. Notice that the relative density has no units. Does 2.7 make sense? Yes, this is the relative density of aluminium.

Example 4: Law of Flotation

Question: A wooden block floats in water with 60% of its volume submerged. The density of water is 1 000 kg/m³. Calculate the density of the wood.

Answer:

Let V be the total volume of the wood. Volume submerged = 0.6V.

By the law of flotation: Weight of wood = Weight of water displaced

ρ_wood × V × g = ρ_water × 0.6V × g

ρ_wood = 0.6 × ρ_water = 0.6 × 1 000 = 600 kg/m³

Answer: The density of the wood is 600 kg/m³.

Units check: the answer is in kg/m³. Notice that the fraction submerged equals the relative density of the wood. This is a useful shortcut: for a floating object, the fraction submerged = RD of the object.

Example 5: Hydrometer

Question: A hydrometer floats in water with 8 cm of its stem above the surface. When placed in another liquid, 6 cm of its stem is above the surface. Calculate the relative density of the liquid.

Answer:

Let the total length of the stem be L and the volume of the hydrometer be V.

In water: Volume submerged = V − A × 0.08 (where A is the cross-sectional area of the stem)

In liquid: Volume submerged = V − A × 0.06

By the law of flotation: Weight of hydrometer = Weight of fluid displaced

In water: W = ρ_water × (V − 0.08A) × g

In liquid: W = ρ_liquid × (V − 0.06A) × g

Equating: ρ_water × (V − 0.08A) = ρ_liquid × (V − 0.06A)

This is complex without knowing V and A. However, in a typical problem, the hydrometer is designed so that the stem is uniform and the volume submerged is approximately equal to the total volume minus the exposed stem. A simpler approach: the relative density is the ratio of the submerged lengths (if the stem is uniform). RD = (L − 0.06) / (L − 0.08). Without L, we cannot solve numerically. Let us assume the hydrometer has a total length of 0.2 m. Then RD = (0.2 − 0.06) / (0.2 − 0.08) = 0.14 / 0.12 = 1.17.

Answer: The relative density of the liquid is approximately 1.17.

Units check: relative density has no units. This problem shows how a hydrometer works — the depth to which it sinks depends on the density of the liquid. In a denser liquid, it sinks less. In a less dense liquid, it sinks more.

6. Graph Work

Graphs help us understand the relationships in floating and sinking.

Upthrust vs depth (for a fully submerged object): If you plot upthrust on the vertical axis and depth on the horizontal axis, you get a horizontal line. Once the object is fully submerged, the upthrust remains constant regardless of depth.

  • Shape: horizontal line.
  • Meaning: upthrust depends on volume displaced, not depth (once fully submerged).

Upthrust vs volume submerged: If you plot upthrust on the vertical axis and volume submerged on the horizontal axis, you get a straight line through the origin. Upthrust is directly proportional to the volume of fluid displaced.

  • Gradient: ρ_fluid × g.
  • Intercept: zero — no volume displaced, no upthrust.
  • Shape: straight line confirms Archimedes' principle.

Apparent weight vs volume submerged: If you plot apparent weight on the vertical axis and volume submerged on the horizontal axis, you get a straight line with a negative gradient. The apparent weight decreases as more of the object is submerged.

  • Gradient: −ρ_fluid × g.
  • Intercept: actual weight (when volume submerged = 0).
  • Shape: straight line confirms W_apparent = W_actual − upthrust.

These graphs help us visualise the relationships in floating and sinking. They turn equations into pictures.

Think of a graph as a map of a relationship. The shape tells you how one quantity changes with another.

7. Practical / Experiment

Practical: Verifying Archimedes' Principle

Apparatus: A spring balance, a stone, a beaker, water, a measuring cylinder, and a retort stand.

Method:

  1. Measure the weight of the stone in air using the spring balance. Record it as W_air.
  2. Fill the measuring cylinder with water to a known level. Record it as V₁.
  3. Lower the stone into the water until it is fully submerged.
  4. Record the new water level as V₂. The volume of the stone is V = V₂ − V₁.
  5. Record the weight of the stone in water as W_water.
  6. Calculate the upthrust: Upthrust = W_air − W_water.
  7. Calculate the weight of water displaced: W_displaced = ρ_water × V × g.
  8. Compare the upthrust with the weight of water displaced. They should be equal.

Calculation: If W_air = 50 N, W_water = 30 N, V = 0.002 m³, ρ = 1 000 kg/m³, g = 10 N/kg:

Upthrust = 50 − 30 = 20 N

Weight of water displaced = 1 000 × 0.002 × 10 = 20 N

They are equal — Archimedes' principle is verified.

Precautions:

  • Zero the spring balance before use.
  • Read the water level at the bottom of the meniscus.
  • Ensure the stone is fully submerged and not touching the sides.
  • Take multiple readings and average them.

Likely source of error: Air bubbles clinging to the stone can affect the volume reading. Tap the stone gently to dislodge bubbles.

This experiment is a classic for a reason. It verifies Archimedes' principle directly and gives you a hands-on understanding of upthrust. Once you see the numbers match, the principle becomes real. It is a beautiful moment in any physics course.

8. Common Mistakes

  • Thinking that heavy objects always sink. A ship is heavy but floats because of its shape.
  • Confusing mass and density. A large object can be light if its density is low.
  • Forgetting that upthrust depends on the volume displaced, not the mass of the object.
  • Thinking that upthrust increases with depth for a fully submerged object. It remains constant.
  • Forgetting to convert units. Volume in m³, density in kg/m³, mass in kg.
  • Confusing relative density with density. Relative density has no units.
  • Thinking that a floating object has no weight. It has weight, but the upthrust balances it.
  • Forgetting that the law of flotation applies only to floating objects. For sinking objects, upthrust is less than weight.

9. Checkpoint Questions

  1. What is upthrust?
    Show answer

    Upthrust is the upward force exerted by a fluid on an object placed in it.

  2. State Archimedes' principle.
    Show answer

    When an object is wholly or partially immersed in a fluid, the upthrust on the object is equal to the weight of the fluid displaced.

  3. State the law of flotation.
    Show answer

    A floating object displaces its own weight of the fluid in which it floats.

  4. Define relative density.
    Show answer

    Relative density is the ratio of the density of a substance to the density of water.

  5. Calculate the upthrust on an object of volume 0.003 m³ fully submerged in water. (ρ = 1 000 kg/m³, g = 10 N/kg)
    Show answer

    Upthrust = ρ × V × g = 1 000 × 0.003 × 10 = 30 N.

  6. Why does a ship float?
    Show answer

    A ship floats because it is hollow and displaces a large volume of water. The upthrust equals the weight of the ship, so it floats.

  7. How does a submarine dive and rise?
    Show answer

    A submarine fills its ballast tanks with water to increase its average density and dive. It pumps air into the tanks to decrease its average density and rise.

  8. Why is ice less dense than water?
    Show answer

    Water expands when it freezes, so the same mass of ice occupies a larger volume than liquid water. This makes ice less dense.

10. Structured Exam-Style Questions

Question 1

(a) State Archimedes' principle. [2]

(b) A stone of volume 0.004 m³ is fully submerged in water. Calculate the upthrust on the stone. Density of water = 1 000 kg/m³, g = 10 N/kg. [3]

(c) The stone weighs 80 N in air. Calculate its apparent weight in water. [3]

Show model answer and marking scheme

(a) When an object is wholly or partially immersed in a fluid, the upthrust on the object is equal to the weight of the fluid displaced. (2 marks.)

(b) Upthrust = ρ × V × g = 1 000 × 0.004 × 10 = 40 N. (3 marks.)

(c) Apparent weight = 80 − 40 = 40 N. (3 marks.)

Question 2

(a) Define relative density and state its significance. [3]

(b) A metal block has a mass of 810 g and a volume of 300 cm³. Calculate its density and relative density. Will it float or sink in water? [5]

(c) Explain why a ship made of steel floats even though steel is denser than water. [3]

Show model answer and marking scheme

(a) Relative density is the ratio of the density of a substance to the density of water. It has no units. RD < 1 means float; RD > 1 means sink. (3 marks.)

(b) Density = 810/300 = 2.7 g/cm³ = 2 700 kg/m³. RD = 2.7. Since RD > 1, it sinks. (5 marks.)

(c) A ship is hollow, so its average density (including the air inside) is less than the density of water. It displaces a large volume of water, and the upthrust equals its weight. (3 marks.)

Question 3

(a) Describe how a hydrometer works. [4]

(b) A wooden block floats in water with 70% of its volume submerged. Calculate the density of the wood. Density of water = 1 000 kg/m³. [4]

(c) Explain why a hot air balloon rises when the air inside is heated. [3]

Show model answer and marking scheme

(a) A hydrometer is a sealed tube with a weighted bulb. It floats in a liquid, and the depth to which it sinks depends on the liquid's density. The relative density is read from the scale at the liquid surface. (4 marks.)

(b) Fraction submerged = RD of wood = 0.7. Density = 0.7 × 1 000 = 700 kg/m³. (4 marks.)

(c) Heating the air inside the balloon makes it expand and become less dense than the surrounding air. The upthrust is greater than the weight, so the balloon rises. (3 marks.)

11. Challenge Questions

Challenge 1

Explain why a person can float more easily in the Dead Sea than in a swimming pool.

Show outline answer

The Dead Sea has a very high salt content, making its water much denser than fresh water. A denser fluid provides more upthrust for the same volume displaced. So a person floats higher in the Dead Sea because the water displaces more weight for the same submerged volume.

Challenge 2

A block of ice floats in water. When it melts, does the water level rise, fall, or stay the same? Explain.

Show outline answer

The water level stays the same. The floating ice displaces its own weight of water. When it melts, it becomes water of the same weight, which occupies the same volume as the water it displaced. So the level does not change.

Challenge 3

Explain why a ship sinks if it is overloaded, using Archimedes' principle.

Show outline answer

A ship floats because the upthrust equals its weight. If it is overloaded, its weight increases. To balance this, it must displace more water, so it sinks deeper. If the weight becomes so great that the ship cannot displace enough water (because the deck goes below the surface), the upthrust can no longer equal the weight, and the ship sinks.

12. Real-World Applications

  • Ships and boats: Float by displacing their own weight of water.
  • Submarines: Control depth by adjusting ballast tanks.
  • Hot air balloons: Rise when the air inside is heated and becomes less dense.
  • Hydrometers: Measure the relative density of liquids.
  • Life jackets: Increase volume, reducing average density to keep a person afloat.
  • Fish: Use swim bladders to control their depth in water.
  • Icebergs: Float because ice is less dense than water.
  • Car batteries: Hydrometers test the density of the acid to check charge.
  • Plimsoll line: Marks maximum safe loading depth for ships.

13. Closing Thought

Floating and sinking are not about weight alone — they are about the delicate balance between an object's weight and the weight of the fluid it displaces. In that balance, we find ships, submarines, and the beauty of Archimedes' principle.

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